data rates question.

I think this info is NTK (Need to know) basis only while the camera is in development. Sufficed to say the Viper has about 2.978Gbs (355MBs) throughput at 1080P.
 
Full sensor full speed 60fps output is around 1GB/s, given that it's 12bit data. You can figure that number out yourself from the number of pixels, bit depth and fps. We're not ready to talk about compressed data yet.

Graeme
 
Graeme_Nattress said:
Full sensor full speed 60fps output is around 1GB/s, given that it's 12bit data. You can figure that number out yourself from the number of pixels, bit depth and fps. We're not ready to talk about compressed data yet.

Graeme
Click to expand...

wait, that's uncompressed?
 
4520 x 2540
RBG 444
12 Bit
60 fps progressive

Hmm, I calculate the data rate to be 3.1 GB/s (1.24 GB/s @ 24 fps). What am I missing?
 
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EDIT: My post is WRONG. Skip this one.

For raw uncompressed data your calculation is right.

I would underestimate it if I would say that this data rate is *just* HUGE.
If this is the case, it's the equivalent of about 1000 Z1s capturing simultaneously to a single computer!!!! :eek:
Or should I say ...supercomputer?

(3.1GB x 8=24.8Gb / 25Mb = 991)
 
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yikes!

I'm aware of a flashmag under development that will record uncompressed 4K @ 60 fps. Presumably RED is working on something similar.
 
Greg Lowry said:
4520 x 2540
RBG 444
12 Bit
60 fps progressive

Hmm, I calculate the data rate to be 3.1 GB/s (1.24 GB/s @ 24 fps). What am I missing?
Click to expand...

This is raw data which means one 12 bit value from each pixel 60 times a second:

4520 x 2540 x 12 x 60 / 1024 / 1024 / 1024 = 7.7 Gbits = 0.96 GBytes
 
Arghhh... IT'S THE BAYER PATTERN......
I thought it was 12bit RGB (12 x 3) SORRY! :embarasse

So to recalculate:
4520 x 2540 x 12 x 60 = 8 266 176 000 (8.26 Gbits) / 8 = 1 033 272 000 (1.03 GBytes/sec)

And my previous comparison with Z1's now will be :
8.26Gbits / 25Mbits = 330 Z1s !!! Now it seems ...easier! :D

Baro, thanks for waking us up, but I think your calculation is wrong. Where did you find those 1024s?
 
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I thought 1 Kbyte = 1024 bytes, 1 Mbyte = 1024 Kbyte, 1 Gbyte = 1024 Mbyte. Isn't that the way you count bytes?
 
baro said:
I thought 1 Kbyte = 1024 bytes, 1 Mbyte = 1024 Kbyte, 1 Gbyte = 1024 Mbyte. Isn't that the way you count bytes?
Click to expand...

You are referring to mebibytes or MiBs (mega binary bytes). 1 megabyte = 10^6 = 1000000 bytes, 1 MiB = 2^20 = 1048576 bytes.

This is useful only in cases that there is strong relation to binary lengths, as in memory chips (RAM, ROM).
It is not used In data rates because there is no point and it is misleading especially when you refer to *bit* rates. You want the actual data rate...

Also the hard disk manufacturers use the megabyte unit to refer to capacities. I know it's confusing some times...
 
I think us old timers will always work in powers of two though. I think the definitions have been subverted from the originals for marketing reasons.

Graeme
 
Well, RED RAID will do it, if you want to keep "in brand". Assuming you can hook up your PC to the camera (no, not over HD SDI for this, over some kind of fibre probably) then sure, you'll be able to record the datastream. You might need to write some code to spool it to a file, but no reason why it shouldn't work, and I don't think we're going to go out of our way to stop you, but I think RED RAID will be a better solution.

Graeme
 
Graeme_Nattress said:
Well, RED RAID will do it, if you want to keep "in brand". Assuming you can hook up your PC to the camera (no, not over HD SDI for this, over some kind of fibre probably) then sure, you'll be able to record the datastream. You might need to write some code to spool it to a file, but no reason why it shouldn't work, and I don't think we're going to go out of our way to stop you, but I think RED RAID will be a better solution.

Graeme
Click to expand...

Will there also be external versions of RED RAID ?

Maybe I'm missing something, but what kind of hard-disc technology (that can fit into this cam) is capable to record at 1GB/s ?
I thought large multiple disc arrays are unavoidable.
 
ooops...
o.k. then. My bad.
Then it IS going to be multiple disc system.
I would choose that over Medea, guessing the design suits the cam...

I suggest the RED SYSTEM package....the cam, lens, storage
...and a keychain :Drogar-BigGrin(DBG)


- for everything else, there is G5....
 
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