Let's start from the beginning:
Every camera has a latitude, a white do black ratiom (i don't know what's the latitude of the HVX200)
So, i suppose that you can get the best from the camera if your set has the same dynamic range as the camera, because if the white to black ratio of the set is lower than the camera,'s latitude you will use fewer bits than the camera is able to capture, and if you stretch them in post, the dynamic range is just stretched, making the picture even worse.
Again if the set dynamic range is larger than the camera is able to capture, you will lose image details.
So the question is:
How the he..aven can i calculate the wattage needed to have a set latitude that is similar to the camera latitude???
Thank you very much guys!
.
Every camera has a latitude, a white do black ratiom (i don't know what's the latitude of the HVX200)
So, i suppose that you can get the best from the camera if your set has the same dynamic range as the camera, because if the white to black ratio of the set is lower than the camera,'s latitude you will use fewer bits than the camera is able to capture, and if you stretch them in post, the dynamic range is just stretched, making the picture even worse.
Again if the set dynamic range is larger than the camera is able to capture, you will lose image details.
So the question is:
How the he..aven can i calculate the wattage needed to have a set latitude that is similar to the camera latitude???
Thank you very much guys!
.
Last edited: