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For dynamic range, I'd go by DxOMark's numbers or a Xyla chart. The Stouffer wedges are not very accurate, especially as you get down to the darkest blacks.
DxOMark is actually fairly accurate for many things, I've found, so I'll take their word on DR, as I don't have a way to properly test DR in an absolute objective manner. However doesn't DxOMark test raw image data? Since video is not raw here, it's going to be compressed data with the tone curve baked in already. I doubt it will do the full 12.8 stops in video.
DxOMark does use raw image data, but the white clipping point (full well capacity) is going to be the same in video....When the tone settings make the shadows noisy, basically all the DR that is there in the raw data is being made available to be recorded by the codec.
So, I'm sticking with 12.8.![]()
But isn't it the case that RAW images are taken directly from the camera's 14-bit A/D converter, while the video gets encoded into 8-bit? Doesn't this have an impact on dynamic range?
But isn't it the case that RAW images are taken directly from the camera's 14-bit A/D converter, while the video gets encoded into 8-bit? Doesn't this have an impact on dynamic range?
Good summary, just a couple of corrections:8 bits of data can only technically record 8 tonal stops of dynamic range - 2^8=256. And you would get 8 stops of sensor dynamic range if the 14 bit to 8 bit downconverter just chose 8 out of the 14 bits worth of information somewhere in the middle of the range (just taking a slice of the data.) However, the downcoverter does use all 14 bits worth of information and shapes it into a data range that will fit within 8 bits (shrinking the pie instead of just taking a slice of the pie.)
Therefore, the very brightest bits and very darkest bits of sensor dynamic range are preserved (which is what were concerned about) just with less tonal steps.
In terms of detail, color, and tonality, raw is always going to be better.
However, 8 bit doesn't have less dynamic range (as we're talking about it) than raw, it has less tonality, which means that the whole image has less tonal detail, including the shadows and highlights. Look at the images at the bottom of this page: http://www.phototechnique.com/how-to/practical-guide-to-dynamic-range/ . The 1 bit image looks completely blown out, but that doesn't necessarily mean it has less dynamic range (as we're talking about it), just that it doesn't have enough available tones to fully describe the detail.
In order to define dynamic range a bit better for those who aren't aware, there are two types of dynamic range at play here. Sensor dynamic range, which is what we're really concerned about and which doesn't really change regardless of how it is recorded, and tonal dynamic range. Sensor DR is defined by full well capacity, or clipping point, divided by the noise floor, or read noise. Tonal dynamic range is defined by the amount of possible tones in an image.
So, 8 bits of data can only technically record 8 tonal stops of dynamic range - 2^8=256. And you would get 8 stops of sensor dynamic range if the 14 bit to 8 bit downconverter just chose 8 out of the 14 bits worth of information somewhere in the middle of the range (just taking a slice of the data.) However, the downcoverter does use all 14 bits worth of information and shapes it into a data range that will fit within 8 bits (shrinking the pie instead of just taking a slice of the pie.)
Therefore, the very brightest bits and very darkest bits of sensor dynamic range are preserved (which is what were concerned about) just with less tonal steps.
Now, less tonal dynamic range does appear to be less sensor dynamic range. If you were looking at a bright cloud, detail just below clipping in 14 bit land can only choose one of two possible options in 8 bit land - 254 or 255. So, you could say that there is less sensor dynamic range in 8 bit, since a bright highlight that wouldn't clip with 14 bits is now clipping with 8 bits (anything over 244.5). But, for highlight and shadow that's only 2 clipping points in 256 possible tones, or 128th less dynamic range than raw. So 12.8 * 127/128 = 12.7 stops of DR, which is close enough to 12.8 to be negligible. (However, we're really splitting hairs here. By using the same math you would say that a 1 bit image has zero dynamic range.)
The great thing about this camera is the options available to use 8 bits worth of data as efficiently as possible in order to maximize those 256 steps of tonal range. Those tonal settings are likely coming directly from raw data, so you're shaping those 14 bits before they're being downconverted to 8 bits.
So, in 8 bits, there is less tonal dynamic range, but sensor dynamic range is the same, or as close as it's going to get in 8 bits, which we have a lot of control over, which means that 12.8 stops of DR is still a valid number.![]()
Hmm, not sure I agree with you.
Basically you are saying that the clipping point of white and black remains the same wether taking RAW stills or compressed video but that there is a much finer graduation (smaller steps) in the RAW image rather than more dynamic range?
In practice, shooting the same scene, I can pull a lot of detail out of the shadows and highlights in the RAW image that just isn't there on the MOV files. While visually the dynamic range might be similar (if not the same), once you start manipulating the image you find that the RAW image can see much further into the shadows and highlights.