Ryan Patrick O'Hara
Veteran
I posted over in EX-1 about rolling shutter reduction. See what they say.
If they disagree with me, they are liars!! lol.
If they disagree with me, they are liars!! lol.
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Bearing I would love for you to further explain how the shutter works in this camera. I am only used to film cameras, not digital.
In film cameras a high shutter speed would mean each frame is exposed at a smaller amount of time, reducing motion blur, and if applicable a wobble (not possible on film, but theoretically would reduce wobble on cmos)
Does the D-90 shutter not work like a real shutter? If it does, wobble should be reduced because it's sampling a smaller unit of time... per frame that is.
Until you clarify, I'm having faith that faster shutter speeds, aka smaller shutter angles will yield more clean results.
I should have put it like this instead:bearing said:The scan rate is fixed. Shutter speed time is defined as the time difference between the resetting pointer and the reading pointer.
Its dark, pixels are zero
0000000000000000
0000000000000000
0000000000000000
0000000000000000
0000000000000000
0000000000000000
Turning on lights, a gray wall.
Turning on camera.
0000000011111111 Camera is starting to reset pixels, 8 so far
1111111111111111 All pixels are taking charge from the light
1111111111111111
1111111111111111
1111111111111111
1111111111111111
1111111100000000 Continuing to reset pixels, 16 so far
2222222222222222 The eight first that were reset are
2222222222222222 starting to recharge
2222222222222222
2222222222222222
2222222222222222
3333333322222222 Continuing to reset pixels, 32 so far
1111111100000000
4444444444444444
4444444444444444
4444444444444444
4444444444444444
Starting to read, 32 pixels behind the resetting pointer.
Red data is in the right matrix.
7777777766666666 4444444444444444 Continuing to reset pixels, 64 so far
5555555544444444 4444444444444444 Reading pixels, 32 so far.
3333333322222222 0000000000000000
1111111100000000 0000000000000000
8888888888888888 0000000000000000
8888888888888888 0000000000000000
9999999999999999 4444444444444444 Continuing to reset pixels, 96 so far,
9999999988888888 4444444444444444 resetting is finished.
7777777766666666 4444444444444444 Still reading pixels, 64 so far.
5555555544444444 4444444444444444
3333333322222222 0000000000000000
1111111100000000 0000000000000000
Final picture will be:
4444444444444444
4444444444444444
4444444444444444
4444444444444444
4444444444444444
4444444444444444
I'll give it a try. It will be very technical, don't know if it will be understandable. Just ask then.
First I want to correct an earlier statement.
I should have put it like this instead:
The scan rate is fixed, the only thing you can change is the exposure time. Exposure time is defined as the time difference between the resetting pointer and the reading pointer. Put in other terms you can say that shutter speed is fixed, only shutter angle is variable.
The sensor is read like a data matrix, starting from the top left corner, going to the right, pixel by pixel in a fixed rate, say 80 MHz.
When the first line is completely read some invisible pixels are read, then the reading continues on the next line. If the amount of horizontal pixels are 1280 then that would have taken 1280/80M seconds which is 16 microseconds. Since there are a number of invisible pixels, say 320, there are 1600 total pixels to be read per line, taking 20 us per line.
An amount of time before pixels are read their charge is reset. That is done in a similar way to how they are read. One at a time their charge is zeroed in the same rate as reading, that is 80 MHz in my example.
If the exposure time is to be 1/500 of a second (which is 2000 microseconds) then the reset of a pixel has to happen 2000 us before reading it. Since one line takes 20 us then a pixel is reset 100 lines before it is being read.
So, if the picture is 720 lines and a slowly moving "band" of 100 of them are exposed at the same time, then we can clearly see how when panning a vertical line becomes angled.
If the exposure time is longer, say 1/48 of a second, then the whole picture is exposed at the same time for the most part, but the start and the end of it is moving in the same slow speed, creating the same effect. Picture is also blurred to a greater extent.
Heres an example of a 16x6 pixel CMOS-sensor taking a picture of a grey wall, just to show how the resetting, reading and exposure is working.
Code:Its dark, pixels are zero 0000000000000000 0000000000000000 0000000000000000 0000000000000000 0000000000000000 0000000000000000 Turning on lights, a gray wall. Turning on camera. 0000000011111111 Camera is starting to reset pixels, 8 so far 1111111111111111 All pixels are taking charge from the light 1111111111111111 1111111111111111 1111111111111111 1111111111111111 1111111100000000 Continuing to reset pixels, 16 so far 2222222222222222 The eight first that were reset are 2222222222222222 starting to recharge 2222222222222222 2222222222222222 2222222222222222 3333333322222222 Continuing to reset pixels, 32 so far 1111111100000000 4444444444444444 4444444444444444 4444444444444444 4444444444444444 Starting to read, 32 pixels behind the resetting pointer. Red data is in the right matrix. 7777777766666666 4444444444444444 Continuing to reset pixels, 64 so far 5555555544444444 4444444444444444 Reading pixels, 32 so far. 3333333322222222 0000000000000000 1111111100000000 0000000000000000 8888888888888888 0000000000000000 8888888888888888 0000000000000000 9999999999999999 4444444444444444 Continuing to reset pixels, 96 so far, 9999999988888888 4444444444444444 resetting is finished. 7777777766666666 4444444444444444 Still reading pixels, 64 so far. 5555555544444444 4444444444444444 3333333322222222 0000000000000000 1111111100000000 0000000000000000 Final picture will be: 4444444444444444 4444444444444444 4444444444444444 4444444444444444 4444444444444444 4444444444444444
So you are saying the rolling shutter is always rolling at it's fastest speed? Changing shutter angle is just exposing the frame for longer/shorter. Does that simply just add or subtract cycles?
That is correct, I think that such fast exposure times are not useful int practice though. If the difference between reset and write is only one line then the exposure time would be 1/50'000 of a second in my example.May I then theorize that the shutter speed can never go faster then the constant speed of the rolling shutter?
Thanks, no deal, it was kind of fun.I am kind of confused, but I think I know where you are coming from.
Thank you for taking the time to explain!
Hey Bearing,
I'm thinking focal length has something to do with the RS effect? Will a longer lens (more magnification) magnify the problem. There was an old school basic rule of thumb that says if your shooting with a 200mm lens that has 4 times magnification.... It also has 4 times the vibration(movement) as a 50mm lens and you would set your shutter speed accordingly.
That clip was just focused at infinity. If you look at when he is done panning left, you can see on the left side of frame down inside of the store- its very sharp.
And, IMO, it looks like it resolves WAY more detail than anything Sub HPX3000 to me. That's just what I see even from Vimeo.
Yeah, you're right. While I'm still pretty stoked about the D90, the PQ just isn't up to par yet. Hopefully it'll get there in the next couple of years with new cameras.I am confused ! maybe my eyes are finally failing me and I need to get to the doctors pretty quick ! ;p
. . . . but these clips simply look no where near as good as any of the current crop of decent HDV cameras (Canon/Sony etc).
EDIT: Forgot to add that with some post work it'll look even better (color grading, downsampling to SD resolution and perhaps a bit of grain etc.).
Theoretically, having a faster shutter speed would reduce the rolling shutter. Faster scans would create less slanted frames.